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Question: 1 / 400

In a 3-hour exam with 320 questions, if there are 40 mathematics problems, how many minutes should be allotted for the math problems if each gets double the time of other questions?

20 minutes

40 minutes

To determine how many minutes should be allotted for the mathematics problems, we first need to calculate the total amount of time available in minutes for the entire exam. A 3-hour exam translates to 180 minutes.

Next, we identify the total number of questions, which is 320, and we know that 40 of these are mathematics problems. This means there are also 280 other types of questions.

If mathematics problems require double the time compared to the other questions, we can establish a time allocation per question. Let’s denote the time allocated for each non-mathematics question as \( x \) minutes. Consequently, each mathematics question would require \( 2x \) minutes.

The total time for the other questions would therefore be \( 280x \) and for the mathematics questions, it would be \( 40 \times 2x \), which equals \( 80x \).

Combining these, the equation for total time becomes:

\[

280x + 80x = 180 \

\]

or

\[

360x = 180

\]

From this, we can solve for \( x \):

\[

x = \frac{180}{360} = 0.5 \text{

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