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Question: 1 / 400

What is the total length of the bridge if one bank holds 1/5 and the other holds 1/6 of its length with the river being 1520 feet wide?

2000 feet

2200 feet

2400 feet

To determine the total length of the bridge, we can represent the length of the bridge as L. According to the information given, one bank holds 1/5 of the bridge's length, and the other bank holds 1/6 of the bridge's length. Therefore, the lengths held by the banks can be expressed mathematically as:

Length held by the first bank = \( \frac{1}{5}L \)

Length held by the second bank = \( \frac{1}{6}L \)

To find the total length of the bridge, we need to add the lengths held by both banks and the part of the bridge that spans the river. The width of the river is given as 1520 feet, representing the central portion of the bridge.

We can establish the equation:

\[

\frac{1}{5}L + \frac{1}{6}L + 1520 = L

\]

Next, to solve for L, we need a common denominator for the fractions, which is 30. Thus, we can convert the fractions:

\[

\frac{1}{5}L = \frac{6}{30}L \quad \text{and} \quad \frac{

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